A#14 (due 2/26)

8.1.2 pg. 400-401 (#16a, 17, 18, 20, 21)

A#14 Handout (front)
A#14 Handout (back)

See 8.1.2 - Interior Angles of a Polygon for more assistance on the material.

EDIT:

Answer Key

im stuck of problem 8-18, i found the missing lengths but im not sure which equation to use for the shape since it has other type of shapes around it   

Valerie H. wrote:

im stuck of problem 8-18, i found the missing lengths but im not sure which equation to use for the shape since it has other type of shapes around it   

Hey! Sorry, I was already asleep last night when you sent this (so I can wake up early like right now haha).

Like we learned with trapezoids, the area of one big shape can also be found by combining areas of smaller shapes. So if we split that shape into a bunch of triangles or triangles with rectangles, etc. then we can just add up those areas.



The blue line gives you a triangle (at the top) with a base of 6 and a height of 3, and the red line gives you a triangle (at the bottom) with a base of 9 and a height of 3. In the middle, you have a rectangle with a base of 9 and a height of 2. Find the areas of all three and add them up for the total area.

I applaud you for being able to find those other side lengths, but always recall what the question is first then figure out what information you actually need. In the case of the perimeter, you'll need those side lengths. For area, you'll need perpendicular items (such as base and height).

By the way, if you're ever stuck (and I don't mean you specifically Valerie), please use the Additional homework help for Chapter 8 thread for any specific problems you're having trouble with. If that site doesn't help you, feel free to ask on here just as you did!